More trisection |
This way is also well known. Here we divide the diagonal, so we divide the width and the height at the same time. |
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The verification is easy. Triangle APT and triangle BCT are similar, and BC=2AP, then BT=2AT. Therefore AT=AB/3. |
This way was presented by KAWAHATA Fumiaki in Origami Tanteidan Newsletter issue 29. |
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The verification is easy, too. Triangle ABP and Triangle CTP are similar, and CP=AP/3, therefore CT=AB/3. |
The next way was presented by NOMA Masamichi in Origami Tanteidan Newsletter issue 14. The advantage of this method is to keep the center part of paper unfolded. |
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Let us verify this. If the length of the side is 1, AP=BP=1/4. Let AT=x, and PT=3/4-x. Apply the Pythagorean theorem at triangle APT and we get (1/4)2+x2=(3/4-x)2, then x=1/3. |